In triangle ABC , AB =AC and BC=AB +AI , where I is the incentre of triangle ABC . Then find the measure of angle A.
Let ABC is an isoscles triangle with AB=BC.A trisector of angle B meets AC at D.If AB,AC and BD are integers and AB BD=3, find AC.
Prove that |(a^2 + λ,ab,ac),(ab,b^2 + λ,bc),(ac,bc,c^2 + λ)| = λ^2(a^2 + b^2 + c^2 + λ) - Sarthaks eConnect | Largest Online Education Community
![geometry - In $\triangle ABC$ with $AB=AC$ and $\angle BAC=20^\circ$, $D$ is on $AC$, with $BC=AD$. Find $\angle DBC$. Where's my error? - Mathematics Stack Exchange geometry - In $\triangle ABC$ with $AB=AC$ and $\angle BAC=20^\circ$, $D$ is on $AC$, with $BC=AD$. Find $\angle DBC$. Where's my error? - Mathematics Stack Exchange](https://i.stack.imgur.com/O6Lat.png)
geometry - In $\triangle ABC$ with $AB=AC$ and $\angle BAC=20^\circ$, $D$ is on $AC$, with $BC=AD$. Find $\angle DBC$. Where's my error? - Mathematics Stack Exchange
If ab + bc + ca = 0, then prove that 1/(a^2-ab)+1/(b^2-ac)+1/(c^2-ab)=0. - Sarthaks eConnect | Largest Online Education Community
ABC is triangle and L, N and M are 3 points respectively on AB, BC and CA such that AL=(2/5) AB, AM=(3/4) AC and AN, CL and BM have a common point.
![From the figure mcos A - AS Given cos A cos B AC AB BC AB Multiply both sides by AB AEX ABBE AB AC – BC In Triangle ABC, AC – From the figure mcos A - AS Given cos A cos B AC AB BC AB Multiply both sides by AB AEX ABBE AB AC – BC In Triangle ABC, AC –](https://toppr-doubts-media.s3.amazonaws.com/images/9114490/9309de7a-714d-4c67-8560-b487301e57a2.jpg)
From the figure mcos A - AS Given cos A cos B AC AB BC AB Multiply both sides by AB AEX ABBE AB AC – BC In Triangle ABC, AC –
![If A, B and C are three points on a line, and B lies between A and C (see below fig.), then prove that AB + BC = AC. If A, B and C are three points on a line, and B lies between A and C (see below fig.), then prove that AB + BC = AC.](https://toppr-doubts-media.s3.amazonaws.com/images/4749190/1136440b-f221-445f-9cd2-dcd59d990ee3.jpg)